Find m<1
32°
350
Оа
32°
Ob
35°
58°
Od
90°

in triangle of 35 degree,

other angle = (35+90)

that is 125.

therefore angles is 180-125= 55 degrees.

for the upper triangle,

same thing.

180-(32+90)=180-122=58 degrees

yes

yes yes yes

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180