Consider parallelogram ABCD with diagonal BD. What values of x and y prove that the parallelogram is a square if CD=20, AD=8x−4, and ∠CBD=4y−3? a. x = 2, y = 12

b. x = 2, y = 23.5

c. x = 3, y = 12

d. x = 3, y = 23.5

x > 1.3

step by step:

8.5−0.9x> 9.8−1.9x

step 1: simplify both sides of the inequality.

−0.9x+8.5> −1.9x+9.8

step 2: add 1.9x to both sides.

−0.9x+8.5+1.9x> −1.9x+9.8+1.9x

1x+8.5> 9.8

step 3: subtract 8.5 from both sides.

1x+8.5−8.5> 9.8−8.5

1x> 1.3

step 4: divide both sides by 1.

1x/1 > 1.3/1

if x = 1, then the answer is 3.5

x^3-4x^2+3x-2/x^2+1

step-by-step explanation:

factor the numerator and denominator and cancel the common factors

did u ever get the answers? i need