Determine the center and radius of the following circle equation: x² + y2 + 2x – 2y – 62 = 0​

Step-by-step explanation:

x²+2x+y²-2y=62

using completing the square

x²+2x+1+y²-2y+1=62+1+1

(x+1)²+(y-1)²=64

(x+1)²+(y-1)²=8²

(x-a)²+(y-b)²=r²

by comparison

(a,b)=(-1,1)

a,b is the center of the circle

r=8unit

r is the radius

  q

step-by-step explanation:

each line from a vertex to the midpoint of the opposite side is called a median. the point where the medians intersect, point q, is the centroid.

the centroid of δabc is point q.

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°