A certain television is advertised as a 55-inch TV (the diagonal length). If the width of the TV is 42 inches, how many inches tall is the TV? Round your answer to the nearest tenth.

69.20in

Step-by-step explanation:

Given data

diagonal of the TV d= 55in

Widht of the TV w=  42 in

Hight h= ???

Applying the Pythagoras theorem

d^2= w^2+ h^2

substitute

55^2= 42^2+ h^2

3025= 1764+ h^2

3025+1764= h^2

4789= h^2

h=√4789

h= 69.20

Hence the Heigth is 69.20in

v = 1/3 a^2h

step-by-step explanation:

if the height is 57.7cm and the height of the slant edge is 18.2cm, then the volume is 1/3 a^2h.