What is an equation of the line that passes through the points (3,1) and (-3, – 7)? Put your answer in fully reduced form.

y = 4/3x - 3

Step-by-step explanation:

Use rise over run to find the slope, (y2 - y1) / (x2 - x1)

Plug in the points:

(y2 - y1) / (x2 - x1)

(-7 - 1) / (-3 - 3)

-8 / -6

= 4/3

Now, plug in the slope and a point into y = mx + b to get the equation:

y = mx + b

1 = 4/3(3) + b

1 = 4 + b

-3 = b

Plug in the slope and y intercept into the equation:

y = 4/3x - 3

So, the equation is y = 4/3x - 3

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

step-by-step :