A plane is 142 km north and 166 km east of an airport. Find x, the angle the pilot should turn in order to fly directly to the airport. Round your answer to the nearest tenth of a degree.

Given:

A plane is 142 km north and 166 km east of an airport as shown in the given figure.

To find:

The value of x to the nearest tenth of a degree.

Solution:

In a right angle triangle,

It is also written as

For the given triangle,

Therefore, the value of x is 40.5 degrees.

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐

ratio is 2 : 9

the answer is three

13.5 : 3