Triangle JKL with vertices J(-3, -2). K(-3, -12). and L(-8, -12): scale factor: k = 1/5, center of dilation: (-13, -2)

point a is the center of the circle that passes through points e, f, and g and the center of the circle that passes through points x, y, and z.

y=3x+4

step-by-step explanation:

given the points a(0,4) and b(-4, -8)

eqn of line ab: (y-4)/(x-0)=(-8-4)/(-4-0)

(y-4)/x=-12/-4=3

y=3x+4

if your equation is in the form ax2 + bx + c, you can find the maximum by using the equation:

max = c - (b2 / 4a).

the first step is to determine whether your equation gives a maximum or minimum.

-x2 + 4x - 2.     thats an example hope it

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