A certain triangle has a base (x) and a height (V). A new triangle is created by tripling the length of the base and quadrupling the height. How does the area of the second triangle compare to the area of the first?
A. 3 times larger
B. 4 times larger
C. 6 times larger
D. 12 times larger
E. 7 times larger

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

do it yourself this is easy

step-by-step explanation:

yeah i know the problem you need. i am taking it right now. the answer is step 3

~mickey