A 30 foot ladder is leaning against the side of a building and is positioned such that the base of the ladder is 21 feet from the base of the building how far above the ground is the point where the ladder touches the building

21.42ft

Step-by-step explanation:

a²+b²=c² where "c" is the hypotenuse of a right triangle and "a" and "b" are the two other sides

now let's plug in the values

21²+b²=30²

b²= 30² - 21²

b²= 459

b= 21.42

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet