Let f(14) = 5 and f'(2) > 3 for 14 < I< 20. How small can f(20) be? By the Mean Value Theorem, for some c E (14, 20)
f'(c)
20 - 14
of'(c)(20 - 14)
Of(c)(20 - 14)
f(c)
20 - 14
F(20) - f(14) =
Replacing f(14) by its value, we get f(20)
Since f'(2) >3, we have f(20) >
this the smallest f(20) can be.

dilation scale factor 2: starting with δabc, draw the dilation image of the triangle with a center at the origin and a scale factor of two. notice that every coordinate of the original triangle has been multiplied by the scale factor (x2). dilation with scale factor 2, multiply by 2.

idkidkdidkdkdidkx

step-by-step explanation:

nndncnd cnn

snddnd

2

step-by-step explanation:

step-by-step explanation:

d would equal 12