Which of the following equations is equivalent to LaTeX: t=\pi m^2-ct = π m 2 − c rewritten for m? Group of answer choices

LaTeX: m=\pm\sqrt{t\pi+c}m = ± t π + c

LaTeX: m=\pm\sqrt{\frac{t+c}{\pi}}m = ± t + c π

LaTeX: m=\pm\sqrt{\frac{t-c}{\pi}}m = ± t − c π

LaTeX: m=\pm\sqrt{\frac{tc}{\pi}}m = ± t c π

The formula LaTeX: d=\sqrt{\frac{h}{6.752}}d = h 6.752 models the relationship of the distance in kilometers d to the horizon and the height in centimeters h of your eyes above the water. Which of the following shows this formula rewritten for h in terms of d?

Group of answer choices

LaTeX: h^2=6.752dh 2 = 6.752 d

LaTeX: h=6.752d^2h = 6.752 d 2

LaTeX: h=\sqrt{\frac{d}{6.752}}h = d 6.752

LaTeX: h=45.589504d^2

this is answer of 144 cubic meters

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.