For #'s 5 - 12: Find the length of the side labeled . Round to the nearest tenth.

for answer 5 - 12 use the below

Step-by-step explanation:

Use SOH CAH TOA to recall how the trig functions fit on a triangle

SOH: Sin(Ф)= Opp / Hyp

CAH: Cos(Ф)= Adj / Hyp

TOA: Tan(Ф) = Opp / Adj

5)

we know the Hyp and the angle and want to find the Opp so use  Sin.. since it's got all of those.

Sin(35) = Opp / 10

10 * Sin(35) = Opp

5.7357 = Opp

x = 5.7 inches

6)

same as 5 but now we want to find the Adj side sooo... use Cos

Cos(54) = Adj / 36     ( from the picture I'm unsure if it's 36 or 35 )

36 * Cos(54) = Adj

21.160 =Adj

x = 21.2 meters

7)

now we know the angle and the Adj side and want to find the Opp , lets use Tan for that

Tan(20) = Opp / 47

47 * Tan(20) = Opp

17.1066 = Opp

x = 17.1 feet

8)

this is identical to 5) but the turned the shape so it looks different, but it's not

Sin(16) = Opp / 18

18 * Sin(16) = Opp

4.9614 = Opp

x = 5.0 cm

9)

this one is another   Opp and Adj  so use Tan again

Tan(65) = Opp / 7.5

7.5 Tan(65) = Opp

16.083 = Opp

x = 16.1 miles

10)

Hyp, angle , Adj, so use Cos

Cos(51) = Adj / 60

60 * Cos(51) = Adj

37.759 = Adj

x = 37.8 feet

11)

angle , Opp, find Hyp  sooo... use Sin

Sin( 36) = 28 / Hyp

Hyp = 28 / Sin(36)  

Hyp = 16.45798

x = 16.5 meters

12)

dealing with Adj, Opp and angle , use Tan again

Tan(60) = 90/ Adj

Adj = 90 / Tan(60)

Adj = 51.961

x = 52.0 inches

step-by-step explanation: a reaction is first order. if the initial reactant concentration is 0.0200 m, and 25.0 days later the concentration is 6.25 x 10-4 m, then its half-life is:

the solution is h=10 because you add 9 to each side of the equation.