The mass of Parcel A was 0.7 kg. Parcel B was heavier than Parcel A. Parcel C had the same mass as Parcel B. The total mass of the three
parcels was 2.5 kg. What was the mass of Parcel C?​

0.9kg

Step-by-step explanation:

Since we are informed that Parcel C had the same mass as Parcel B, let their mass be represented by x.

Therefore,

Parcel A + Parcel B + Parcel C = 2.5

0.7 + x + x = 2.5

0.7 + 2x = 2.5

2x = 2.5 - 0.7

2x = 1.8

x = 1.8/2

x = 0.9

The mass of parcel C is 0.9kg

it 2

step-by-step explanation:

8^1/3=2

hello :

by applying the distributive property :

6 × 4.3 = 6 × ( 4 + 0.3 )

            =   (6 ×   4) + (6 ×   0.3)

            = 24 + 1.8

6 × 4.3 = 25.8