Each side of a regular hexagon has a length of 2 ft 3 in. Find the perimeter of the regular hexagon

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Step-by-step explanation:

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t is a regular hexagon of side 2′. So it can be divided into 6 triangles equal in all respects.The sum of all interior angle of hexagon =(n-2)*180 = (6–2)180 =720 deg. each interior angle =720/6 =120 deg.Side of the triangle divides this angle into two equal halves each = 60 deg.when two base angles of each triangle are 60 and 60 third angle will also become 60 making it as equilateral triangle. N ow the area of hexagon =6*the area of each equilateral triangle of base 2 ft.=6*1/2*2*h. h is the altitude of the triangle=2/2*tan 60 = rt3 =1.732 .NOW area of hexagon =6*1.732 = 10.392 sq.ft

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option

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step-by-step explanation: