XU Z) = 0.6.
Mathematics, 05.03.2021 01:50 raymond5799
X, Y and Z are three mutually exclusive events.
P(X) = 0.4, P(Y) = 0.3 and P(
XU Z) = 0.6.
Find:
() P(XUY)
(i) P(Z)
(ii) The probability that none of X, Y or Z
happens
Answers: 2
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X, Y and Z are three mutually exclusive events.
P(X) = 0.4, P(Y) = 0.3 and P(
XU Z) = 0.6.
XU Z) = 0.6.
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