An archer releases an arrow with an initial velocity of 20 feet per second at a height of 12 feet. The path the arrow takes can be modeled using the function f(x)=−16x2+20x+12, where f(x) represents the height, in feet, of the arrow and x represents the time the arrow travels in seconds. What is the maximum height, in feet, reached by the arrow? Round your answer to the nearest hundredth if necessary. Do not include units in your answer

18.25

Step-by-step explanation:

The arrow reaches its highest point at the y-value of the turning point. Thus, we need to find the maximum quadratic function.

-16x^2+20x+12

We know that the maximum( or minimum) of a parabola is reached at x= -b/(2a)= -20/ 2(-16)= 18.25

Showing that the object will reach a maximum height of 18.25 feet

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: