Suppose that in a certain country, 10% of the elderly people have diabetes (call this Event D). It is also known that 30% of the elderly people are living below poverty level (call this Event P), 35% of the elderly population falls into at least one of these categories, and 5% of the elderly population falls into both of these categories. If a randomly selected elderly person is living below the poverty level, what is the probability that she/he has diabetes

0.1667 = 16.67% probability that she/he has diabetes

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

In which

P(B|A) is the probability of event B happening, given that A happened.

is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Living below the poverty level.

Event B: Having diabetes.

30% of the elderly people are living below poverty level.

This means that

5% of the elderly population falls into both of these categories.

This means that

If a randomly selected elderly person is living below the poverty level, what is the probability that she/he has diabetes

0.1667 = 16.67% probability that she/he has diabetes

let m = monomial

let t = trinomial

so, m times t = t.

monomial times a trinomial = another trinomial.