4. Iron combines with 4.00 g of Copper (11) nitrate to form 6.01 g of Iron (l) nitrate and 0.400 g copper metal. How much iron did it take to convert the Cu (N03)2?

what i would say the best answer is a. 40.5

jml angle lkj & angle mj = lm

answer: b.36 feet

step-by-step explanation:

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.