A rectangle is 6 feet long and 4 feet wide. If each dimension is increased by the same number of feet, a new rectangle is formed whose area is 39 square feet more than the area of the original rectangle. By how many feet was each dimension increased?​

Each dimension increased by 3 ft.

Step-by-step explanation:

Area of the original rectangle = 4 * 6 = 24 square feet

Increased dimension = x ft

New length = 6 + x

New width = 4 +x

New area = (6 + x)(4 +x)    {Use FOIL method}

                = 6*4 + 6*x + x*4 + x*x

                = 24 + 6x + 4x + x²

                = x² + 10x + 24

New area = 24 + 39

x² + 10x + 24 = 63

x² +10x + 24 - 63 = 0

x² + 10x  - 39 = 0

x² + 13x - 3x  - 3*13 = 0

x (x + 13) - 3(x + 13) = 0

(x + 13)(x -3) = 0   {Ignore x + 13, as it gives negative value}

x - 3 = 0

x = 3

x/3-10=8

x/3=18

x=48

on monday rodney ate 1/4th of the sandwich = 3/12

on tuesday he ate 1/3rd of the sandwich = 4/12

therefore in total he has eaten = 3/12 + 4/12 = 7/12

thus we can say that he has eaten 7/12 of the sandwich on monday and tuesday alltogether.

happy to

pls mark as brainliest.