Someone help plz this is do tonight plz Find the equation in point-slope form of the line shown in the graph.

Step-by-step explanation:

Write the equation of line in slope-intercept form. Line parallel to the y-axis that passes through the point (77,88)

Find the equation of the line which is perpendicular to the line y= − 1/3 x+6 through the point (2,4).

Find the slope of the line passing through each of the following pairs of points and draw the graph of the line. (−1, 4), (−1, −3)

up

step-by-step explanation:

the orientation of the parabolas can easily be found by analysing the power of x and y and their signs. if x is squared , parabola opens up and also if its coefficient is negative it opens down. if y is squared , the parabola opens right and also if its coefficient is negative it opens left. however in order to do the above analysis our equation must be in standard form .

our parabola is

which is not standard form of any parabola . hence we square on both hand side and convert it into standard form.

hence we see that x is squared and its coefficient is non negative . there for it opens up.

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