​​ \frac{7}{9}v+\frac{5}{12}-\frac{3}{ 18}v\geq \frac{3}{4}v+\frac{1}{3} 9
7
​
v+
12
5
​
−
18
3
​
v≥
4
3
​
v+
3
1
​

y=mx+

27

step-by-step explanation:

area of rectangle a is 2 times that of rectangle b that means 2x+x =   36cm^2

3x = 36cm ^2

x = 36/3

x= 12cm^2

and 2x = 24cm^2

now side of square = are divided by sides = 36/4 = 6cm

that means length of rectangle a and b is 6cm too

now for rectangle a,

l*b = area

= 6*y=24

y=24/6 = 4

therefore dimensions of rectangle a are- length = 6cm, breadth = 4cm

and for rectangle b, length = 6cm and breadth = 6-4 = 2cm.

hope this .

the answer is a and d