The length of a rectangle is 12 less than the width find the length and width of the rectangle if the area is 160 square meters

the width is 13.11meter and the length is 1.11meter

Step-by-step explanation:

let the width be x and the length be x-12

area = 160 = l×b = x×x-12

x×x-12 = 160

x^2 = 172

x= 13.11

thus, the width is 13.11 and the length is 1.11

answer: 2/4

step-by-step explanation:

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.