What are the first four terms of the sequence: f(n) = 3n(n+3)

First four terms would be n = 1, 2, 3, 4

f(1) = 3 ( 1 )( 1 + 3 )
= 3 * 4
=12
f(2) = 3 ( 2 )( 2 + 3 )
= 6 * 5
= 30
f(3) = 3 ( 3 )( 3 + 3 )
= 9 * 6
= 54
f(4) = 3 ( 4 )( 4 + 3 )
= 12 * 7
= 84