Jesse and Benjamin are asked to factor 100x^2−100. Here are their solutions. Who is correct? Jesse
100x^2−100=(10x)^2−10^2
=(10x-10)(10x+10)
=10(x-1)(10)(x+1)
=100(x-1)(x+1)

Benjamin
100x^2-100=100(x^2-1)
=100(x-1)(x+1)

24+x=y

step-by-step explanation:

step-by-step explanation :

we know that

the measurement of the outer angle is the semi-difference of the arcs which comprises

in this problem

m< xzy is the outer angle

substitute the values

the measure of angle xoy is equal to

> by central angle

substitute the value