Find the surface area of a square pyramid with side length 5 ft and slant height 7 ft. 5 ft
5 ft

99.33ft^2

Step-by-step explanation:

The surface area of a square pyramid is expressed as;

TSA = a²+2a√a²/4 + h²

Given that

a = 5ft

h = 7ft

Substitute

TSA = 5²+2(5)√5²/4 + 7²

TSA = 25+10√25/4 + 49

TSA = 25 + 10√(221/4)

TSA = 25 + 10(√55.25)

TSA = 25 + 10(7.433)

TSA = 25 +  74.33

TSA = 99.33ft^2

Hence the surface area of a square pyramid with side length 5 ft and slant height 7 ft is 99.33ft^2

the entire expression should be subtracted from 30. to subtract the quantity, distribute the negative sign, which changes the signs on the terms. so, the –2 changes to positive and gets added to 30 instead of subtracted from it.

hope this ! ^w^

none cuz there are no "following statements" regarding the question

step-by-step explanation: