Suppose there is a 1.9°F drop in temperature for every thousand feet that an airplane climbs into the sky. If the temperature on the ground is 48.8°F​, what will be the temperature when the plane reaches an altitude of 8,000 ft​?

(6,1)(5,4)slope = (4 - 1) / (5 - 6) = 3/-1 = -3y = mx + bslope(m) = -3use either of ur , = 6 and y = 1now sub and find b, the y int1 = -3(6) + b1 = -18 + b1 + 18 = b19 = bso ur equation is : y = -3x + we need it in standard formy = -3x + 3x to both sides3x + y = 19 < == standard form