Water and oil are mixed in the ratio 3:5. Find the density of the mixture if the density of water is 1g/cm ^3 and that of oil is 0.8g/cm^3

Density of mixture is 7.0 g/.

Step-by-step explanation:

Density of mixture = density of water in the mixture + density of oil in the mixture

Given: water and oil were mixed in a ratio 3:5

           density of water is 1.0 g/ and that of oil is 0.8 g/.

Then,

density of water in the mixture = 3 x 1.0 g/

                                   = 3.0 g/

Density of the volume of water in the mixture is 3.0 g/.

density of oil in the mixture = 5 x 0.8 g/

                                              = 4.0 g/

Density of oil in the mixture is 3.0  g/.

So that,

Density of mixture = 3.0 + 4.0

                               = 7.0

Density of mixture is 7.0 g/.

circle area = pi * radius^2

if diameter = 10 then radius = 5

circle area = pi * 5^2

circle area = pi * 25

circle area = 78.5398163397 square units

step-by-step explanation:

i think the length is 12 and the width is 17