HEL MEEE OU??? On what day of the year 2009 was the year 250 000 minutes old? Give the month and day

Explanation:

1 hour = 60 minutes

1 day = 24 hours

1 day = (24 hrs)*(60 min/1hr) = 24*60 min = 1440 min

1 day = 1440 min

Divide 250,000 minutes over 1440 min to convert from minutes to days

(250,000)/(1440) = 173.611

This means 250,000 minutes is approximately 173.611 days.

We round this down to the nearest whole number because 174 full days means that some portion of minutes has not elapsed just yet. In other words, we're still on day 173. Yes we're past the halfway point, but we're still on this day.

From here, bring out a Day-Of-Year Calendar which will help you locate any day of the year if you know its numeric value, and vice versa. For instance, if you selected any value between 1 and 31, then you'll be on January of that day number. If you selected 32, then you'll be on February 1st since day 32 is one day after day 31 (the last day in January). The largest value of the calendar is either 366 on leapyears or 365 for non-leapyears.

Keep in mind that 2009 is not a leapyear, so that means we won't be involving Feb 29. On non-leapyears, the 173rd day lands on June 22nd.

You could count out the number of days from Jan 1st until you count out 173 days (you should land on June 22). Though I don't recommend this method because it could be error prone and slow.

Side note: Day-Of-Year Calendars are useful if you want to know the timespan between any two days of the year. For instance, June 22 is the 173 day of the year while Oct 9th is the 282 day of the year (I'm focusing on a non-leapyear). The difference in value is 282-173 = 109, meaning that 109 days elapse from June 22 to Oct 9.

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Step-by-step explanation:

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}

fa tha first one you gonna add y to both sides

it look like this

x-y+y=6+y

x=y+6

therefore your answer is

x =y+6

fa tha second one

you gonna flip tha equation

it gonna look like x-4y=y

then add 4 to both sides

it gonna look like tha

x-4 +4 =y +4

so therefore tha answer is x=y+4

step-by-step explanation: