Two cars leave the same parking lot, with one heading north and the other heading east. After several minutes, the northbound car has traveled 1 mile, and the eastbound car has traveled 4 miles. Measured in a straight line, how far apart are the two cars? If necessary, round to the nearest tenth.​

distance between two cars in a straight line = 4.12 miles

Step-by-step explanation:

The North and East make a right angle and if you make a straight line between the two cars you will make a right angled triangle.

Now we can use Pythagoras theorem to calculate the distance between two cars in a straight line.

p = 1

b = 4

h = ?

Using Pythagoras theorem

h² = p² + b²

h² = 1² + 4²

h² = 1 + 16

h² = 17

h = sqroot (17)

h = 4.12 miles

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

the answer is:

the correct option:

b.

to solve the problem, we need to remember how to operate to simplify exponential expressions using the logarithms.

we are given the equation:

then, using placing logarith with base 7 on both sides of the equation, we have:

so, rounding the obtained result to two decimal places (nearest hundreth), we have:

hence, we have that the correct option:

b.

have a nice day!