Using the product rule of differentiation , evaluate the derivative of g(x) = (2x3-5x)(7x+9)

G’(x)=d/dx((2x^3-5x)(7x+9))
g’(x)=d/dx(14x^4+18x^3-35x^2-45x)
g’(x)= d/dx(14x^4)+d/dx(18x^3)+d/dx(-35x^2)+d/dx(-45x)
g’(x)=14(4x^3)+18(3x^2-35)2x-45
g’(x)= 56x^3+54x^2-70x-45 (answer)

2.4+3.2t. you get the answer by adding the ones with variables and ones without