An earthworm accelerates from a speed of 0.01 m/s to 0.02 m/s over a distance of 0.9 m. How long did it take?

t = 60.0 s

Step-by-step explanation:

d = ½at² + v₀t + d₀

   d is displacenemt

   v₀ is initial velocity

   d₀ is initial position

v² = v₀² + 2ad

0.02² = 0.01² + 2a(0.9)

0.0004 = 0.0001 + a(1.8)

a(1.8) = 0.0003

a = 0.0001667 m/s²

d = ½at² + v₀t

0.9 = ½(0.0001667)t² + 0.01t

0.0000834t² + 0.01t – 0.9 = 0

t² + (119.976)t – 10791 = 0

t = 60.0 s