A shop keeper buys 20kg of sugar at Birr y per kg. he sells 16kgs at Birr (y+3/4) per kg and the rest at Birr (y+1) per kg. what is his profit.​

The profit is $16

Step-by-step explanation:

From the question, we have 20 kg at Birr y per kg

The cost price is thus;

20 * y = 20y Birr

Now for the selling price;

16 kg was sold at (y + 3/4) Birr per kg

we have here that;

16 * y + 3/4 * 16

= 16y + 12

The rest is thus; 20 - 16 = 4 kg

The rest of this at (y + 1) per kg will be

4 * (y + 1) = 4y + 4

The total selling price is thus;

4y + 4 + 16y + 12 = 20y + 16

The profit is the difference between the selling and cost price

We have this as:

20y + 16 - 20y

= $16

step-by-step explanation:

equation

you are asked to write the equation

  expression = 0

using the given expression. when you do that, you have

  2x^2-2x-12 = 0

factoring

you can see that each of the coefficients is even, so a factor of 2 can be removed immediately.

  2(x^2 -x -6) = 0

if you multiply the binomials (x+a)(x+b), you get

  (x +a)(x +b) = x^2 +(a+b)x +ab

this tells you the coefficient of x is the sum of two factors of the constant term. here, that means -1 is the sum of two factors of -6. we want to know those factors so we can factor the trinomial.

  -6 = -1×6 = -2×3 = -3×2 = -6×1

the factor pair that sums to -1 is {-3, 2}, so our factorization is

  2(x -3)(x +2) = 0

solutions

the solutions to this equation are the values of x that make the product zero. a product is zero only when only of the factors of the product is zero. here, that means

  x - 3 = 0

  x = 3 . . . add 3 to both sides of the equation

or

  x +2 = 0

  x = -2 . . . add -2 to both sides of the equation

the solutions to the equation are x=3 or x=-2. both of these values of x satisfy the equation—they make it be true.

answer: b

step-by-step explanation: