find the number such that three times the sum of two and a number is three less than four times the number​

9

Step-by-step explanation:

let the number be n then 3 times the sum of 2 and the number is

3(n + 2) = 4n - 3 ( 3 less than 4 times the number )

3n + 6 = 4n - 3 ( subtract 3n from both sides )

6 = n - 3 ( add 3 to both sides )

9 = n

That is the number is 9

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

the barter