Which expression is equivalent to (3x^2+4x-7)(x-2) A. x(3x^2+4x-7)+2(3x^2+4x-7)
B.(3x^2+4x-7)(x)+(3x^2+4x-7)(-2)< br />C. x(3x^2+4x-7)-2
D.2x(3x^2+4x-7)​

sorry man i accidentally pressed yes my bad

step-by-step explanation:

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752

the answer is 13

step-by-step explanation:

5*5=25

12*12=144

25+144=169

169^2=13