A university researcher wants to estimate the mean number of novels that seniors read during their time in college. An exit survey was conducted with a random sample of 9 seniors. The sample mean was 7 novels with standard deviation 2.29 novels. Assuming that all conditions for conducting inference have been met, which of the following is a 94.645% confidence interval for the population mean number of novels read by all seniors? A. 7 + or - 1.960 (2.29/underroot 8).
B. 7 + or - 1.960 (2.29/underroot 9).
C. 7 + or - 2.262 ((2.29/underroot 9).
D. 7 + or - 2.306 (2.29/underoot 8).
E. 7 + or - 2.306 (2.29/underoot 9).

Population mean = 7 ± 2.306 ×

Step-by-step explanation:

Given - A university researcher wants to estimate the mean number

            of  novels that seniors read during their time in college. An exit

            survey was conducted with a random sample of 9 seniors. The

            sample mean was 7 novels with standard deviation 2.29 novels.

To find - Assuming that all conditions for conducting inference have

              been met, which of the following is a 94.645% confidence

              interval for the population mean number of novels read by

              all seniors?

Proof -

Given that,

Mean ,x⁻ = 7

Standard deviation, s = 2.29

Size, n = 9

Now,

Degrees of freedom = df

                                = n - 1

                                = 9 - 1

                                = 8

⇒Degrees of freedom = 8

Now,

At 94.645% confidence level

α = 1 - 94.645%

   =1 - 0.94645

  =0.05355 ≈ 0.05

⇒α = 0.5

Now,

  = 0.025

Then,

 = 2.306

∴ we get

Population mean = x⁻ ± ×

                           = 7 ± 2.306 ×

⇒Population mean = 7 ± 2.306 ×

sas (side angle side)

aa (angle angle)

sss(side side side)

sas find two sides with an angle in between

aa is finding two angles and the third will add up to 180

sss find all sides

step-by-step explanation: