philip has 11 coins that equal a total of 82 cents. His coins include at least 1 quarter 1 dime 1 nickel and 1 penny. how many of each coin does he have

Philip has 1 Quarter, 3 Dimes, 5 Nickels, and 2 Pennys.

Step-by-step explanation:

Given that Philip has 11 coins that equal a total of 82 cents, and his coins include at least 1 quarter 1 dime 1 nickel and 1 penny, to determine how many of each coin does he have the following calculation must be performed:

Quarter = 0.25

Dime = 0.10

Nickel = 0.05

Penny = 0.01

0.82 - 0.25 - 0.10 - 0.05 - 0.01 = 0.41

0.41 = 0.10 x 4 + 0.1 (5 coins + 4 previous coins = 9 coins).

0.41 = 0.10 x 2 + 0.05 x 4 + 0.01 (7 coins + 4 previous coins = 11 coins).

0.25 + (3 x 0.1) + (5 x 0.05) + (2 x 0.01) = X

0.25 + 0.30 + 0.25 + 0.02 = X

0.82 = X

Thus, Philip has 1 Quarter, 3 Dimes, 5 Nickels, and 2 Pennys.

your answer is b ^w^ hope i

answer: y = -2.5x - 15

              (-6,0)

step-by-step explanation: