A football player kicked the ball from on top of a platform. The flight of a kicked football follows the quadratic function f(x) = - 0.02x ^ 2 + 2.2x + 12 f(x) is the vertical distance in feet and the horizontal distance the ball travels. which is the highest point the football will reach, in feet? Round to one decimal place.

The highest point the football will reach is of 180.5 feet.

Step-by-step explanation:

Vertex of a quadratic function:

Suppose we have a quadratic function in the following format:

It's vertex is the point

In which

Where

If a<0, the vertex is a maximum point, that is, the maximum value happens at , and it's value is .

In this question:

The height of the ball is given by the following equation:

Which is the highest point the football will reach, in feet?

This is the value of f at the vertex.

We have that:

So

The highest point the football will reach is of 180.5 feet.

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine