Decoration of line passing through PT (3 ,2) close and perpendicular to line y is equals to X is​

y = -x+5

Step-by-step explanation:

The equation of the line in point slope form is expressed as;

y - y0 = m(x-x0)

Get the slope

Given the equation of the line as y = x

The slope of the line is m = 1

The slope of the line perpendicular =M =-1/1

M = -1

Using the slope M = -1 and the point (3, 2) to get the required equation;

y - y0 = m(x-x0)

y - 2 = -1(x-3)

y - 2 = -x+3

y+x = 3 + 2

y = -x + 5

Hence the required equation is y = -x+5

the answer is (-4,-4)

hope this ! : d