It is due today please help me.

(a) The range of the function represents the set of values on the y-axis. We see that function has an absolute maximum, then the range of the function is:

(b) The location of the maximum is represented by its ordered pair. After direct observation, we located this maximum at

(c) By direct observation we find that the value of when is -12.

(d) By direct observation we conclude that the values of when are -4.8 and 2.

Step-by-step explanation:

(a) The range of the function represents the set of values on the y-axis. We see that function has an absolute maximum, then the range of the function is:

(b) The location of the maximum is represented by its ordered pair. After direct observation, we located this maximum at

(c) By direct observation we find that the value of when is -12.

(d) By direct observation we conclude that the values of when are -4.8 and 2.

a4 - 3a2 - 1

step-by-step explanation:

step   1   :

equation at the end of step   1   :

  ((a4) -   3a2) -   1

step   2   :

trying to factor by splitting the middle term

2.1     factoring   a4-3a2-1  

the first term is,   a4   its coefficient is   1 .

the middle term is,   -3a2   its coefficient is   -3 .

the last term, "the constant", is   -1  

x = 25

step-by-step explanation:

a^2+b^2=c^2

7^2+24^2=c^2

49+576=625

sqrt625=25

x=25