How many solutions does the equation 8x + 38 = -3(-6 - 4x) has?

Step-by-step explanation:

8x + 38 = -3(-6 - 4x)

8x + 38 = -3(-4x - 6)

8x + 38 = -3 (-4x - 6)

8x + 38 = 12x + 18

8x +38 = 12x + 18

8x + 38 - 38 = 12x + 18 - 38

8x + 38 - 38 = 12x + 18 - 38

8x = 12x + 18 - 38

8x= 12x - 20

8x = 12x - 20

8x - 12x = 12x - 20 - 12x

8x - 12x = 12x - 20 - 12x

-4x = 12x - 20 -12x

-4x = 12x - 20 -12x

-4x = - 20

-4x = -20

X = 5

a complex number is a number that can be expressed in the form a + bi, where a and b are real numbers, and i is a solution of the equation x2 = −1. because no real number satisfies this equation, i is called an imaginary number. has no real solution, since the square of a real number cannot be negative.

answer: the answer is one of

step-by-step explanation:   we are given to write a proper fraction where the whole is divided into an even number of equal parts less than ten, and an odd number of those parts exist.

an even number less than 10 may be one of 2, 4, 6 or 8. so, the whole may be one of these four evens.

now, an odd number of these parts must exist, so the numerator must be an odd number, one of 1, 3, 5 or 7. it cannot be 9 because then the fraction will become improper.

thus, our fraction may be one of the following