Three friends are travelling by aeroplane and want to pay as little as possible in total for their luggage. The airline rules are:
Every passenger may carry 10 kg of luggage for free.
Every extra 1 kg above this costs $5.
The maximum amount of luggage any one passenger may carry is 20 kg.
In total, the three friends are carrying four items weighing 6 kg, 7 kg, 9 kg and 12 kg. item of luggage. What is the least total cost for their luggage?
A $20 B $25 C $30 D $35
Anyone may
carry any

B.25$

Step-by-step explanation:

to make the money less one of the freinds will carry 9kg and the other 12 kg the last one carries the left luggage weighing 7kg and 6kg which add up to 13kg.

the first freind won't pay anything as he is passing 9kg luggage

the second will pay : 12-10 =2 so 2kg*5$=10$

the last freind will pay 13-10=3 so 3kg*5$=15$

to find the total money the pay we will add 10$ and 15$ which became 25$.

hope this helped.

hi

step-by-step explanation:

see attached

step-by-step explanation:

given the function as;

write the equation replacing f(x) with y

form   and fill a table containing values of y with corresponding values of x

you can take a range for   values of x as -3≤x≤3

solving for x=-3

for x=-2

repeat the same procedure to get the values of y for the remaining ,x=-1 to x=3

plot the values of y against values   of x and obtain the following graph