A ball is dropped from a height of 192 inches onto a level floor. After the third bounce it is still 3 inches off the ground. Presuming that the height the ball bounces is always the same fraction of the height reached on the previous bounce, what is that fraction?

The required fraction =

Step-by-step explanation:

Let the required fraction =

Given: Initial height = 192 inches

Height of ball after second bounce =

Height of ball after third bounce =

After the third bounce it is 3 inches off the ground.

So,

Hence, The required fraction =

g(x) = x² + 2

step-by-step explanation:

it is given that the graphs are the same shape.

the only difference is that the red graph is 2 units higher than the blue graph.

that is to say that the red graph is simply the blue graph that has been moved vertically by 2 units in the positive y direction.

hence

g(x) = f(x) + 2

or

g(x) = x² + 2

ian gonna lie that is way to much