Adam has 6x dollars. Jimmy has $10 more than Adam. Paul has 2x dollars less than Jimmy. a.) Find how much money Jimmy has in terms of x.
b.) Find how much money Paul has in terms of x.
c.) If x = 5, how much money does Paul have?

a Adam=6x

b Jimmy=6x+10

c Paul's money= 6x+10-2x

=4x+10

if x=5

Paul's money=4(5)+10

=20+10

=30

Step-by-step explanation:

a=6x

j=a+10=6x+10

p=j-2x=6x+10-2x=4x+10

A) j=6x+10

B) p=4x+10

C) p(5)=4(5)+10=20+10=30

(a) {a₁, a₁r, a₁r², … a₁rⁿ⁻¹, …}

(b) $59 398

step-by-step explanation:

(a) the annual sequence of profits

aₙ = a₁rⁿ⁻¹

the model for the sequence of profits is {a₁, a₁r, a₁r², … a₁rⁿ⁻¹, …} .

(b) profit after 15 yr

  a₁ = $ 30 000

  r = 1.05

a₁₅ = 30 000 × 1.05¹⁴

a₁₅ = 30 000 × 1.979 93

a₁₅ = $59 398

the profit in year 15 will be $59 398.