I WILL MARK BRAINLIEST IF CORRECT! Pls also give an explanation! The sides of a square are 4 units long. One vertex of the square is located at (-1,1) on the standard (x, y) coordinate plane. Which of the following points could also be a vertex of the square?

a. (-3,3)
b. (-5,-3)
c. (3,3)
d. (-5,3)
e. (4,5)

There is no solution (since none has side length of 4 units)

Step-by-step explanation:

If V (-1,1) is one of vertex of a square, then the next vertex to V distance must be the known value of 4

VA: V to (-3,3)   = √(-1 - -3)² + (1 - 3)² = √8 = 2.8

VB: to (-5,-3)     = √(-1 - -5)² + (1 - -3)² = √32 = 5.7

VC: o (3,3)        = √(-1 -3)² + (1 - 3)² = √20 = 4.47

VD: to (-5,3)      = √(-1 - -5)² + (1 - 3)² = √20 = 4.47

VE: to (4,5)        = √(-1 - 4)² + (1 - 5)² = √41 = 6.4

529 and 531

step-by-step explanation:

answer: 48

just remember to use pemdas:

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