A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find the maximum height reached by the rocket, to the nearest tenth of a foot. y= -16x² +198x+148​

x=0))

Step-by-step explanation:

S we want to find when the rocket will hit the ground (height=0 also y=0) so let setup the equation

-16x2+148x+128=0 (we can divide out a -4 so let's do that)

4x2-37x-32=0, now you can use the quadratic formula)

(37±sqrt(372-4(4)(-32))/(2*4)=x, x=10.046 & x=-.796 (we want the positive number because we want the time AFTER the launch (which is where x=0))

4400

step-by-step explanation:

example 2 – simplify: step 1: completely factor both the numerators and denominators of all fractions. step 2: change the division sign to a multiplication sign and flip (or reciprocate) the fraction after the division sign; essential you need to multiply by the reciprocal. step 3 : cancel or reduce the fractions.