The lengths of the sides of hexagon H are 1, 2, 3, 4, 5, and 6. If no two consecutive sides of H have consecutive-integer lengths, what
is the maximum sum of the lengths of three consecutive sides of H?

Hehevf iwkefrvnjendc

Step-by-step explanation:

d. bc = 12 and ef = 16

step-by-step explanation:

we are given that δabc : δdef such that .

also, it is given that

so, from the options, we need that .

a.

b.

c.  

d.

as, we can see that only option d gives the same ratio as i.e. .

hence, the possible lengths are bc = 12 and ef = 16.

1/3 + 1/3 ≠ 2/6 because 1/3 alone = 2/6  

step by step explanation:

1/3 + 1/3 = 2/3       2/3=4/6