Can I have help with this question please?

Step-by-step explanation:

you want to use the slope intercept formula,  and you may as well remember this,  you'll need it often  

y = mb + b

where m = the slope of the line. and is , for later math , the derivative :) any way

perpendicular means going perfectly across, and also the slope is a reciprocal of the line we are going orthogonal to  ( another way of saying perpendicular, but more for 3D things. )

y = 1/3 x - 3

we want the 1/3  and then the reciprocal  so  3/1 or just 3  and then the negative of that so -3   :)  

now use the point given (3,2) to choose where the ling passes thur the y axis. so when x=3 , then y = 2, use the point slope formula

y - y1 = m(x-x1)

now plug in the given point and the slope that was figured out

y-2 =-3(x-3)    (distribute the 3 and move the 2 over )

y = -3x +9 +2

y = -3x +11  

that's a perfectly fine perpendicular line to the given line.

the correct answer is c