Find the sum of the infinite geometric sequence:
8, 4, 2, 1, ​

The common ratio is 1/2 or 0.5 . If you multiply the current term by the the common ratio the the output will be the next term.

8⋅1/2=4

4⋅1/2=2

2⋅1/2=1 etc ...

because the absolute value of r is less than 1 we can use the following formula.

a/1−r where a is the first term and r is the common ratio

In our problem

a=8 and r=0.5

Substitute

8/1−0.5=8/0.5=16

The sum of this infinite geometric series is 16.

Also, another formula you can use that is guaranteed to work every time, no matter what, is:

Sn=a(r^n−1/r−1)

All the variables work the same way as above, and "n" is the number of terms in the series. So, say you wanted to find the sum of the first 10 terms and were to substitute everything in:

S10=8(0.5^10−1/0.5−1)

S10=15.984375

Therefore the sum if the series is 15.98!

Step-by-step explanation:

add them

step-by-step explanation:

idk you did not give the options or numbers so you cant solve it