What is an equation of the line that is perpendicular to y- 3 = -4(x + 2) and passes through the point (-5, 7)?
O A. y-7=-4(x + 5)
O B. y+7--(-5)
O C. y-7-1(x+5)
O D. y+ 7 = 4(x - 5)
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it appears the answer options are typed incorrectly

Step-by-step explanation:

First of a line perpendicular to another line has the inverse opposite slope

    if  m is the slope  m of line 1  the perpendicular line slope is   -1/m

y - 3 = -4(x + 2)    equarion 1

y - 3 = -4x - 8       -4 × (x+2)

y = -4x - 5            added 3 to both sides to get the y intercept form y=mx+b

the slope of the perpendicular line will be   1/4

using the point slope method

y - y1 = m(x -x1)    

the gives the (x,y) point of the perpendicular as (-5, 7)

x1 = -5

y1 = 7

y - 7 = 1/4(x - (-5))

y - 7 = 1/4(x +5)     <--------------   Answer

the attached graph shows the line and the perpendicular going through point (-5, 7)

man its nopq i just guessed and got it right so uhh

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step-by-step explanation:

in english this is

ex.15 pag.85 create. write in ten lines the continuation of the ballad of the five motanasi, using verbs to the imperfect and to the perfect compound. five stars

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