Question Completion Status: QUESTION 5
(06.03)
How can
3
Ix-2= 1x + 11 be set up as a system of equations?
зу - х = -6
4y - x = 44
зу + х = -6
4y + x = 44
3y - 3x = -6
4y - 4x = 44
зу + 3x = -6
4y + 4x = 44

y-y1=4(x-x1)

step-by-step explanation:

this is point-slope form since you only have 4 as the slope it goes in place of m

hope this : )

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.

the answer is c: divide the arc's degree measure by 360°, then multiply by the circumference of the circle.